?a?????t 3DG2383 ????????3???????e???1 1 ?????? 3DG2383 1 npn e??????1e?1|a???1 ??????????a ??????a ?y?? ?t?y?a???1ye?t1??? o?1??? ?????1?? ae?? t o -92mod 2 ??e? 2.1 ???t? 3y?e1?? t am b = 25 2? y ?? 3? ?o? ???? ??? ???? - l?????1 v ce0 1 6 0 v ???? - ? ????1 v cb0 1 6 0 v l??? - ? ????1 v eb0 6 v ????? i c 1 . 0 a o?1|a (t a=25 ) p tot 0 . 9 w ??a t j 1 5 0 ???a? t stg - 5 5 150 1.4 5 e c b 1.4 5 5.1 max 6.1 max 8.7 max 12. 7min 2.1 0.5 0.5 2.2 ?2?y 3y?e1?? t am b = 25 1? ? ? 2? y ?? 3? ? o? 2a ? ? ?t ?e? ?e ?? ??? ???? - ??????1? i cb0 v cb =150v , i e = 0 1 a l??? - ??????1? i eb0 v eb =6v ,i c = 0 1 a r 6 0 1 2 0 o 1 0 0 2 0 0 12l????y????? ??2?? h fe v ce =5v , i c =200m a y 1 6 0 3 2 0 ???? - l???o??1 v cesat i c =500m a, i b =50m a 1 . 5 v ???a f t v ce =5v ,i c =200m a 2 0 m h z ?? ?-????t?yeo?aa 14 o? ?? 05 10 58 07 22 8-22 68 229 9 ??? 05 10 580 03 60 ? 1 3 12 2 3
?a?????t 3DG2383 3 ?e???? 100 05 0 p to t (w ) 0.45 0.90 t ( ) 0 0 0.4 0.8 v ce (v) i c (a) 0.6 0.2 24 6 8 i c -v ce 1????? p tot -t am b 1????? 8m 2ma i b =1m a v ce sat (v) h fe i c (a) i c (a) 1 0. 1 0. 01 10 10 0 0. 01 0. 1 0. 001 0. 1 1 v cesat -i c 1????? h fe -i c 1????? t am b =25 i c /i b =10 t am b =25 v ce =5v ? 2 3 12 2 3
|
